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Beliebt Geometry >

foki y=(2x+5)^2

Lösung

foki

y = (2 x + 5)^{2}

Lösung

(- \frac{5}{2}, \frac{1}{16})

Schritte zur Lösung

Rewrite

y = (2 x + 5)^{2}

in the standard form:

4 \cdot \frac{1}{16} (y - 0) = (x - (- \frac{5}{2}))^{2}

(h, k) = (- \frac{5}{2}, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(- \frac{5}{2}, 0)

along the y-axis

(- \frac{5}{2}, 0 + p)

= (- \frac{5}{2}, 0 + \frac{1}{16})

Fasse zusammen

(- \frac{5}{2}, \frac{1}{16})

Graph

Beliebte Beispiele

f oc i x^{2} = - 2 y

f oc i x \leq y^{2}

foki 4x^2-8x-3y-2=0

f oc i 4 x^{2} - 8 x - 3 y - 2 = 0

f oc i x = 4 y^{2}

foki 3x^2-30x+77

f oc i 3 x^{2} - 30 x + 77