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Beliebt Geometry >

foki y=(2x)^2

Lösung

foki

y = (2 x)^{2}

Lösung

(0, \frac{1}{16})

Schritte zur Lösung

Rewrite

y = (2 x)^{2}

in the standard form

4 \cdot \frac{1}{16} (y - 0) = (x - 0)^{2}

(h, k) = (0, 0), p = \frac{1}{16}

Parabola is symmetric around the y-axis and so the focus lies a distance

p

from the center

(0, 0)

along the y-axis

(0, 0 + p)

= (0, 0 + \frac{1}{16})

Fasse zusammen

(0, \frac{1}{16})

Graph

Beliebte Beispiele

f oc i x^{2} - 2 x + 8

foki-3x^2-12x-9

f oc i - 3 x^{2} - 12 x - 9

f oc i 4 x^{2} - 4 x^{1}

foki y=-x^2+2x-3

f oc i y = - x^{2} + 2 x - 3

f oc i y = 1 - x - x^{2}