0=2x^2-y-12x+11

Lösung

0 = 2 x^{2} - y - 12 x + 11

(h, k) = (3, - 7), p = \frac{1}{8}

Schritte zur Lösung

0 = 2 x^{2} - y - 12 x + 11

Rewrite

0 = 2 x^{2} - y - 12 x + 11

in the standard form

4 \cdot \frac{1}{8} (y - (- 7)) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, - 7), p = \frac{1}{8}

4 u^{2} + 20 v = 0

y \leq - x^{2}

5 x^{2} + 25 x + 10 y = 15

x^{2} - 8 x - 10 y - 4 = 0

0.2 x^{2} - 0.8 x - 0.2 = o