Y^2=4X

Lösung

Y^{2} = 4 X

(h, k) = (0, 0), p = 1

Schritte zur Lösung

Y^{2} = 4 X

Rewrite

Y^{2} = 4 X

in the standard form:

4 \cdot 1 \cdot (X - 0) = (Y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = 1

- y^{2} - x + 2 = 0

y \geq x^{2} - 7 x + 10

p x^{2} = - 20 y

(y + 5)^{(2)} = - 2 (x - 7)

(x - 3)^{2} = 8 (y + 5)