x-1y^2-1y-1=0

Lösung

x - 1 y^{2} - 1 y - 1 = 0

(h, k) = (\frac{3}{4}, - \frac{1}{2}), p = \frac{1}{4}

Schritte zur Lösung

x - 1 \cdot y^{2} - 1 \cdot y - 1 = 0

Rewrite

x - 1 \cdot y^{2} - 1 \cdot y - 1 = 0

in the standard form

4 \cdot \frac{1}{4} (x - \frac{3}{4}) = (y - (- \frac{1}{2}))^{2}

Therefore parabola properties are:

(h, k) = (\frac{3}{4}, - \frac{1}{2}), p = \frac{1}{4}

2 y = x^{2} - 6 x + 9

y = x^{2} + 10 x - 171

y^{2} = - 17 x

2 (y^{2} - 6 y + 18) = x - 54

x^{2} - 4 z + 5 = 0