x^2+4x-8y+28=0

解答

x^{2} + 4 x - 8 y + 28 = 0

(h, k) = (- 2, 3), p = 2

求解步骤

x^{2} + 4 x - 8 y + 28 = 0

将

x^{2} + 4 x - 8 y + 28 = 0

改写为标准形式

4 \cdot 2 (y - 3) = (x - (- 2))^{2}

因此抛物线性质是:

(h, k) = (- 2, 3), p = 2

(y - 2)^{2} = - 4 x

(10 + y) 2 - y^{2} = - 3 x + 12

(y - 3)^{2} = - 20 (x + 2)

3 a - 5 (b - a) = (a - b) \cdot (a + b) - a (a - 1)

0 = x^{2} + 14 x - 4 y + 48