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Beliebt Geometry >

4y^2+x-32y+68=0

Lösung

4 y^{2} + x - 32 y + 68 = 0

Lösung

(h, k) = (- 4, 4), p = - \frac{1}{16}

Schritte zur Lösung

4 y^{2} + x - 32 y + 68 = 0

Rewrite

4 y^{2} + x - 32 y + 68 = 0

in the standard form

4 (- \frac{1}{16}) (x - (- 4)) = (y - 4)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 4), p = - \frac{1}{16}

Graph

Beliebte Beispiele

(y-8)^2=24(x+1)

(y - 8)^{2} = 24 (x + 1)

x^2-40x+16y+160=0

x^{2} - 40 x + 16 y + 160 = 0

x^{2} + (y - 1) = 4

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r^{2} - 7 t + 6 = 0