x^2+4x-8y+20=0

Lösung

x^{2} + 4 x - 8 y + 20 = 0

(h, k) = (- 2, 2), p = 2

Schritte zur Lösung

x^{2} + 4 x - 8 y + 20 = 0

Rewrite

x^{2} + 4 x - 8 y + 20 = 0

in the standard form

4 \cdot 2 (y - 2) = (x - (- 2))^{2}

Therefore parabola properties are:

(h, k) = (- 2, 2), p = 2

y^{2} + 2 y + 6 x + 4 = 0

2 y^{2} + x + 6 = 8 y

x + y^{2} = 64

y \leq x^{2} - 6 x

y + 4 = (x - 1)^{2}