x^2+6x-4y-3=0

Lösung

x^{2} + 6 x - 4 y - 3 = 0

(h, k) = (- 3, - 3), p = 1

Schritte zur Lösung

x^{2} + 6 x - 4 y - 3 = 0

Rewrite

x^{2} + 6 x - 4 y - 3 = 0

in the standard form

4 \cdot 1 \cdot (y - (- 3)) = (x - (- 3))^{2}

Therefore parabola properties are:

(h, k) = (- 3, - 3), p = 1

x^{2} - 3 y = 0

x^{2} - 3 y = 4

(x - 5)^{2} = - 20 (y - 1)

y = \frac{4 x + 2}{y}

(y - 1)^{2} = - 2 (x - 2)