-y^2+x+4=0

Lösung

- y^{2} + x + 4 = 0

(h, k) = (- 4, 0), p = \frac{1}{4}

Schritte zur Lösung

- y^{2} + x + 4 = 0

Rewrite

- y^{2} + x + 4 = 0

in the standard form:

4 \cdot \frac{1}{4} (x - (- 4)) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- 4, 0), p = \frac{1}{4}

x^{2} + 4 x - y = 0

3 x^{2} + 9 y = 0

5 x^{2} - 8 y + 3 = 0

5 - 2 (g (x)) = 8 x^{2} - 14 x + 11

x^{2} + 6 x + y + 10 = 0