y-48<= x^2-14x

Lösung

y - 48 \leq x^{2} - 14 x

(h, k) = (7, - 1), p = \frac{1}{4}

Schritte zur Lösung

y - 48 \leq x^{2} - 14 x

Rewrite

y - 48 \leq x^{2} - 14 x

in the standard form

4 \cdot \frac{1}{4} (y - (- 1)) = (x - 7)^{2}

Therefore parabola properties are:

(h, k) = (7, - 1), p = \frac{1}{4}

x^{2} - 8 x + p (x) = 0

r + \frac{a}{n} = b^{2}

x = 4 (y - 1)^{2}

y^{2} = 2 x + 4

y > - (x + 4)^{2}