y^2+2y+1=-2x+4

Lösung

y^{2} + 2 y + 1 = - 2 x + 4

(h, k) = (2, - 1), p = - \frac{1}{2}

Schritte zur Lösung

y^{2} + 2 y + 1 = - 2 x + 4

Rewrite

y^{2} + 2 y + 1 = - 2 x + 4

in the standard form

4 (- \frac{1}{2}) (x - 2) = (y - (- 1))^{2}

Therefore parabola properties are:

(h, k) = (2, - 1), p = - \frac{1}{2}

x - 8 y^{2} = 0

x = \frac{y ^{2}}{7}

y^{2} - 5 y - 8 = 5 x

x^{2} - 6 x - 3 y - 6 = 0

2 x^{2} + 3 x + y = - 4