4x^2+6x^2+4x-2y=0

解

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

(h, k) = (- \frac{1}{5}, - \frac{1}{5}), p = \frac{1}{20}

解答ステップ

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

4 x^{2} + 6 x^{2} + 4 x - 2 y = 0

を標準的な形式で書き換える

4 \cdot \frac{1}{20} (y - (- \frac{1}{5})) = (x - (- \frac{1}{5}))^{2}

ゆえに放物線の特性は:

(h, k) = (- \frac{1}{5}, - \frac{1}{5}), p = \frac{1}{20}