x^2-6x-4y+29=0

Lösung

x^{2} - 6 x - 4 y + 29 = 0

(h, k) = (3, 5), p = 1

Schritte zur Lösung

x^{2} - 6 x - 4 y + 29 = 0

Rewrite

x^{2} - 6 x - 4 y + 29 = 0

in the standard form

4 \cdot 1 \cdot (y - 5) = (x - 3)^{2}

Therefore parabola properties are:

(h, k) = (3, 5), p = 1

x^{2} - 3 x - y = 0

x^{2} = - 2 + u (x)

x^{2} - 6 y + 4 x + 5 = 0

x = 8 y^{2} + 1

x 2 x + 8 y = 8