10y=-5x^2+8

Lösung

10 y = - 5 x^{2} + 8

(h, k) = (0, \frac{4}{5}), p = - \frac{1}{2}

Schritte zur Lösung

10 y = - 5 x^{2} + 8

Rewrite

10 y = - 5 x^{2} + 8

in the standard form:

4 (- \frac{1}{2}) (y - \frac{4}{5}) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{4}{5}), p = - \frac{1}{2}

(x - 3) 2 + \frac{y ^{2}}{4} = 1

x = 2 x - y^{2}

(y + 2)^{2} = 16 x

x^{2} - 6 x + y + 5 = 0

x^{2} - k (x) - x = 0