10x+y=-x^2+2

Lösung

10 x + y = - x^{2} + 2

(h, k) = (- 5, 27), p = - \frac{1}{4}

Schritte zur Lösung

10 x + y = - x^{2} + 2

Rewrite

10 x + y = - x^{2} + 2

in the standard form

4 (- \frac{1}{4}) (y - 27) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, 27), p = - \frac{1}{4}

8 x^{2} + 5 x + k (x) = 0

3 x^{2} + 4 y = 12

y^{2} = 3 x - 3

y < x^{2} + 1

x^{2} + 4 x + 2 y = 0