4x^2+41k(x)+10=0

Lösung

4 x^{2} + 41 k (x) + 10 = 0

(h, k) = (0, - \frac{10}{41}), p = - \frac{41}{16}

Schritte zur Lösung

4 x^{2} + 41 y + 10 = 0

Rewrite

4 x^{2} + 41 y + 10 = 0

in the standard form:

4 (- \frac{41}{16}) (y - (- \frac{10}{41})) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, - \frac{10}{41}), p = - \frac{41}{16}

x = 8 - y^{2}

x + y^{2} = 49

16 y^{2} = 120 x - 225

x^{2} + 7 x - k (x) = 0

2 x + y^{2} = 3