What is 4x^2+9y^2-36=0 ?

The solution to 4x^2+9y^2-36=0 is Ellipse with (h,k)=(0,0),a=3,b=2

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4x^2+9y^2-36=0

4 x^{2} + 9 y^{2} - 36 = 0

(h, k) = (0, 0), a = 3, b = 2

Solution steps

4 x^{2} + 9 y^{2} - 36 = 0

Rewrite

4 x^{2} + 9 y^{2} - 36 = 0

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{3 ^{2}} + \frac{( y - 0 ) ^{2}}{2 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 3, b = 2

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 3, b = 2

y = \frac{1}{4} x^{2}

9 x^{2} - 4 y^{2} - 90 x - 32 y = - 305

f (x) = x^{2} - 6 x + 2

\frac{y ^{2}}{25} - \frac{x ^{2}}{16} = 1

\frac{( x + 3 ) ^{2}}{16} + \frac{( y - 5 ) ^{2}}{25} = 1

What is 4x^2+9y^2-36=0 ?
The solution to 4x^2+9y^2-36=0 is Ellipse with (h,k)=(0,0),a=3,b=2