3x^2-12x+q(x)=0

Lösung

3 x^{2} - 12 x + q (x) = 0

(h, k) = (2, 12), p = - \frac{1}{12}

Schritte zur Lösung

3 x^{2} - 12 x + y = 0

Rewrite

3 x^{2} - 12 x + y = 0

in the standard form

4 (- \frac{1}{12}) (y - 12) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 12), p = - \frac{1}{12}

(x - 1)^{2} = 8 (y - 0)

4 x + y^{2} - 7 = 0

4 x = 2 y^{2} - 4 y - 23

x = 10 y - 24 - y^{2}

(y - 2)^{2} = 3 (x - 2)