3x^2+12y=0

Lösung

3 x^{2} + 12 y = 0

(h, k) = (0, 0), p = - 1

Schritte zur Lösung

3 x^{2} + 12 y = 0

Rewrite

3 x^{2} + 12 y = 0

in the standard form:

4 (- 1) (y - 0) = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = - 1

x^{2} + 3 y = 7

1.5 t^{2} - 11.25 t + 4.21875 + d = 0

3 y^{2} - 4 x = - 1

x - y^{2} + 1 > 0

y + 6 x = x^{2} + 6