y^2=5x+1

Lösung

y^{2} = 5 x + 1

(h, k) = (- \frac{1}{5}, 0), p = \frac{5}{4}

Schritte zur Lösung

y^{2} = 5 x + 1

Rewrite

y^{2} = 5 x + 1

in the standard form:

4 \cdot \frac{5}{4} (x - (- \frac{1}{5})) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{5}, 0), p = \frac{5}{4}

x^{2} - 2 x + 2 y + 3 = 0

x^{2} + 6 x + 3 y + 12 = 0

x^{2} - 2 x - y = 0

(x + 1)^{2} = 8 (y - 3)

5 x^{2} + 4 x - 10 y + 39 = 0