-f(x)=2x^2+x-1

Lösung

- f (x) = 2 x^{2} + x - 1

(h, k) = (- \frac{1}{4}, \frac{9}{8}), p = - \frac{1}{8}

Schritte zur Lösung

- y = 2 x^{2} + x - 1

Rewrite

- y = 2 x^{2} + x - 1

in the standard form

4 (- \frac{1}{8}) (y - \frac{9}{8}) = (x - (- \frac{1}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{1}{4}, \frac{9}{8}), p = - \frac{1}{8}

x^{2} + 5 x - \frac{1}{4} y + 6 = 0

1 - x^{2} - y = 0

x^{2} - 2 y + 1 = 0

v^{2} = v^{2} + 2 a s

(x + 1)^{2} = 32 (y - 0)