exzentrizität (y^2)/(25)-((x+1)^2)/(16)=1

Lösung

exzentrizität

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1

\frac{41}{5}

Dezimale

1.28062 \dots

Schritte zur Lösung

= \frac{a ^{2} + b ^{2}}{a}

Calculate Hyperbola properties

\frac{y ^{2}}{25} - \frac{( x + 1 ) ^{2}}{16} = 1 :

Up-down Hyperbola with

(h, k) = (- 1, 0), a = 5, b = 4

= \frac{5 ^{2} + 4 ^{2}}{5}

Fasse zusammen

= \frac{41}{5}

ecce n t r i c i t y + \frac{y ^{2}}{16} - \frac{x ^{2}}{9} = 1

ecce n t r i c i t y \frac{y ^{2}}{36} - \frac{x ^{2}}{9} = 1

ecce n t r i c i t y 16 x^{2} - 25 y^{2} = 100

ecce n t r i c i t y 9 (y - 2)^{2} - 4 x^{2} = 36

ecce n t r i c i t y \frac{y ^{2}}{4} - \frac{x ^{2}}{5} = 1