x^2+4y-4x=0

Lösung

x^{2} + 4 y - 4 x = 0

(h, k) = (2, 1), p = - 1

Schritte zur Lösung

x^{2} + 4 y - 4 x = 0

Rewrite

x^{2} + 4 y - 4 x = 0

in the standard form

4 (- 1) (y - 1) = (x - 2)^{2}

Therefore parabola properties are:

(h, k) = (2, 1), p = - 1

y - 9 x^{2} = 1

y^{2} - 6 y + 24 x + 57 = 0

f (x) = x^{2} - 466 x + 8064

6 (y + 4) = - (x - 1)^{2}

3 x^{2} + y - 1 = 0