-y^2+2x=0

Lösung

- y^{2} + 2 x = 0

(h, k) = (0, 0), p = \frac{1}{2}

Schritte zur Lösung

- y^{2} + 2 x = 0

Rewrite

- y^{2} + 2 x = 0

in the standard form:

4 \cdot \frac{1}{2} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{2}

7 x^{2} + 4 y - 24 = 0

(x - 4)^{2} = 4 (y + 2)

r 2 r = - 9 + 6 q

x = 5 y^{2} - 3

x - 8 = - \frac{1}{20} (y + 2)^{2}