center ((x-5)^2)/(36)-(y^2)/(64)=1

Lösung

center

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

(5, 0)

Schritte zur Lösung

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

Rewrite

\frac{( x - 5 ) ^{2}}{36} - \frac{y ^{2}}{64} = 1

in the form of a standard hyperbola equation

\frac{( x - 5 ) ^{2}}{6 ^{2}} - \frac{( y - 0 ) ^{2}}{8 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (5, 0), a = 6, b = 8

And the center is:

(5, 0)

ce n t er y^{2} - \frac{x ^{2}}{9} = 1

ce n t er 16 x^{2} - 9 y^{2} - 64 x - 18 y + 199 = 0

ce n t er 9 x^{2} - 16 y^{2} - 18 x - 64 y - 199 = 0

ce n t er \frac{y ^{2}}{25} - \frac{x ^{2}}{81} = 1

ce n t er 9 x^{2} - 16 y^{2} - 54 x + 64 y - 127 = 0