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Beliebt Geometry >

center 25x^2-16y^2+50x+128y-631=0

Lösung

center

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

Lösung

(- 1, 4)

Schritte zur Lösung

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

Rewrite

25 x^{2} - 16 y^{2} + 50 x + 128 y - 631 = 0

in the form of a standard hyperbola equation

\frac{( x - ( - 1 ) ) ^{2}}{4 ^{2}} - \frac{( y - 4 ) ^{2}}{5 ^{2}} = 1

Therefore Hyperbola properties are:

(h, k) = (- 1, 4), a = 4, b = 5

And the center is:

(- 1, 4)

Graph

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