-f(x)=3x^2+4x-4

Lösung

- f (x) = 3 x^{2} + 4 x - 4

(h, k) = (- \frac{2}{3}, \frac{16}{3}), p = - \frac{1}{12}

Schritte zur Lösung

- y = 3 x^{2} + 4 x - 4

Rewrite

- y = 3 x^{2} + 4 x - 4

in the standard form

4 (- \frac{1}{12}) (y - \frac{16}{3}) = (x - (- \frac{2}{3}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{2}{3}, \frac{16}{3}), p = - \frac{1}{12}

y - 3 = x^{2}

x^{2} - 5 x - y + 6 = 0

x^{2} + 3 y = 6

4 x^{2} + 3 x + h (x) = 0

2 x^{2} + 3 x + k (x) = 0