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Frequently Asked Questions (FAQ)
What is the foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 ?
- The foci ((y-3)^2)/(8^2)-((x-2)^2)/(8^2)=1 is (2,3+8sqrt(2)),(2,3-8sqrt(2))