(2x-1)^2+(3x-1)^2=y^2

解

(2 x - 1)^{2} + (3 x - 1)^{2} = y^{2}

(h, k) = (\frac{5}{13}, 0), a = \frac{1}{13}, b = \frac{1}{13}

解答ステップ

(2 x - 1)^{2} + (3 x - 1)^{2} = y^{2}

(2 x - 1)^{2} + (3 x - 1)^{2} - y^{2} = 0

を標準的な双曲線のequationで書き換える

\frac{( y - 0 ) ^{2}}{( \frac{1}{13} ) ^{2}} - \frac{( x - \frac{5}{13} ) ^{2}}{( \frac{1}{13} ) ^{2}} = 1

ゆえに双曲線の特性は:

(h, k) = (\frac{5}{13}, 0), a = \frac{1}{13}, b = \frac{1}{13}