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受欢迎的 Geometry >

solvefor x,h(x)^2=13x^2-6x+1

解答

求解

x, h (x)^{2} = 13 x^{2} - 6 x + 1

解答

x = \frac{3 + h - 4}{13 - h}, x = \frac{3 - h - 4}{13 - h}; h \neq = 13

求解步骤

h x^{2} = 13 x^{2} - 6 x + 1

交换两边

13 x^{2} - 6 x + 1 = h x^{2}

将

h x^{2}

para o lado esquerdo

13 x^{2} - 6 x + 1 - h x^{2} = 0

改写成标准形式

a x^{2} + b x + c = 0

(13 - h) x^{2} - 6 x + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( 13 - h ) \cdot 1}{2 ( 13 - h )}

化简

(- 6)^{2} - 4 (13 - h) \cdot 1 : 2 h - 4

x_{1, 2} = \frac{- ( - 6 ) \pm 2 h - 4}{2 ( 13 - h )}; h \neq = 13

将解分隔开

x_{1} = \frac{- ( - 6 ) + 2 h - 4}{2 ( 13 - h )}, x_{2} = \frac{- ( - 6 ) - 2 h - 4}{2 ( 13 - h )}

x = \frac{- ( - 6 ) + 2 h - 4}{2 ( 13 - h )} : \frac{3 + h - 4}{13 - h}

x = \frac{- ( - 6 ) - 2 h - 4}{2 ( 13 - h )} : \frac{3 - h - 4}{13 - h}

二次方程组的解是:

x = \frac{3 + h - 4}{13 - h}, x = \frac{3 - h - 4}{13 - h}; h \neq = 13

作图

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