2400^2x^2=460^2(x^2+z^2+36)

解答

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

(h, k) = (0, 0), a = \frac{138}{13871}, b = 6

求解步骤

240 0^{2} x^{2} = 46 0^{2} (x^{2} + z^{2} + 36)

将

240 0^{2} x^{2} - 46 0^{2} (x^{2} + z^{2} + 36) = 0

改写为标准双曲线方程形式

\frac{( x - 0 ) ^{2}}{( \frac{138}{13871} ) ^{2}} - \frac{( z - 0 ) ^{2}}{6 ^{2}} = 1

因此双曲线的性质为:

(h, k) = (0, 0), a = \frac{138}{13871}, b = 6

24 = a^{2} - b^{2}

9 x^{2} - 25 y^{2} + 200 y = 625

f (x) (f (x)) = x^{2} + \frac{1}{4}

\frac{( y + 2 ) ^{2}}{30} - \frac{( x - 1 ) ^{2}}{8} = 1

- 2 x^{2} + y^{2} - 4 = 0