x=5y^2

Lösung

x = 5 y^{2}

(h, k) = (0, 0), p = \frac{1}{20}

Schritte zur Lösung

x = 5 y^{2}

Rewrite

x = 5 y^{2}

in the standard form:

4 \cdot \frac{1}{20} (x - 0) = (y - 0)^{2}

Therefore parabola properties are:

(h, k) = (0, 0), p = \frac{1}{20}

3 x^{2} - 9 y + 8 = 0

x - y^{2} = 20

(y - 1)^{2} = 8 (x - 3)

y^{2} + 8 y + 4 x + 20 = 0

(y - 4)^{2} = - 8 (x - 1)