achse 5x^2+2y^2=50

Lösung

achse

5 x^{2} + 2 y^{2} = 50

semi - major axis b = 5, semi - minor axis a = 10

Schritte zur Lösung

5 x^{2} + 2 y^{2} = 50

Rewrite

5 x^{2} + 2 y^{2} = 50

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 10 ) ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 10

a x i s \frac{( x - 2 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{16} = 1

a x i s \frac{( x - 2 ) ^{2}}{4} + \frac{( y - 3 ) ^{2}}{1} = 1

a x i s \frac{( x + 1 ) ^{2}}{64} + \frac{( y - 1 ) ^{2}}{100} = 1

a x i s 4 x^{2} + 25 y^{2} + 24 x + 250 y = - 561

a x i s 16 x^{2} + 25 y^{2} + 224 x + 250 y - 191 = 0