achse (x^2)/(36)+(y^2)/(16)=1

Lösung

achse

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

semi - major axis a = 6, semi - minor axis b = 4

Schritte zur Lösung

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

Rewrite

\frac{x ^{2}}{36} + \frac{y ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{6 ^{2}} + \frac{( y - 0 ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 6, b = 4

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 6, b = 4

a x i s \frac{x ^{2}}{16} + (y - 4)^{2} = 1

a x i s 49 x^{2} + 64 y^{2} = 25

a x i s x^{2} + 4 y^{2} = 1

a x i s \frac{( x - 2 ) ^{2}}{4} + \frac{( y + 2 ) ^{2}}{9} = 1

a x i s 16 x^{2} + 4 y^{2} = 25