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Beliebt Geometry >

achse x^2+4y^2=10

Lösung

achse

x^{2} + 4 y^{2} = 10

Lösung

semi - major axis a = 10, semi - minor axis b = \frac{5}{2}

Schritte zur Lösung

x^{2} + 4 y^{2} = 10

Rewrite

x^{2} + 4 y^{2} = 10

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{( 10 ) ^{2}} + \frac{( y - 0 ) ^{2}}{( \frac{5}{2} ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 10, b = \frac{5}{2}

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (0, 0), a = 10, b = \frac{5}{2}

Graph

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