exzentrizität 4x^2+y^2=4x

Lösung

exzentrizität

4 x^{2} + y^{2} = 4 x

\frac{3}{2}

Dezimale

0.86602 \dots

Schritte zur Lösung

= \frac{b ^{2} - a ^{2}}{b}

Calculate ellipse properties

4 x^{2} + y^{2} = 4 x :

Ellipse with center

(h, k) = (\frac{1}{2}, 0), b = 1, a = \frac{1}{2}

= \frac{1 ^{2} - ( \frac{1}{2} ) ^{2}}{1}

\frac{1 ^{2} - ( \frac{1}{2} ) ^{2}}{1} = \frac{3}{2}

= \frac{3}{2}

ecce n t r i c i t y \frac{x ^{2}}{6} + \frac{y ^{2}}{12} = 1

ecce n t r i c i t y \frac{( x - 8 ) ^{2}}{9} + \frac{( y - 3 ) ^{2}}{4} = 1

ecce n t r i c i t y 9 x^{2} + 16 y^{2} - 18 x - 64 y - 71 = 0

a x i s 9 x^{2} + 4 y^{2} = 36

a x i s 4 x^{2} + 9 y^{2} = 36