exzentrizität ((x)^2)/(49)+((y)^2)/(36)=1

Lösung

exzentrizität

\frac{( x ) ^{2}}{49} + \frac{( y ) ^{2}}{36} = 1

\frac{13}{7}

Dezimale

0.51507 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{49} + \frac{y ^{2}}{36} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 7, b = 6

= \frac{7 ^{2} - 6 ^{2}}{7}

\frac{7 ^{2} - 6 ^{2}}{7} = \frac{13}{7}

= \frac{13}{7}

ecce n t r i c i t y 16 x^{2} + 4 y^{2} + 96 x - 24 y + 116 = 0

ecce n t r i c i t y x^{2} + 4 y^{2} - 4 x - 8 y - 92 = 0

ecce n t r i c i t y \frac{x ^{2}}{49} + \frac{y ^{2}}{25} = 1

ecce n t r i c i t y x^{2} + \frac{y ^{2}}{4} = 1

ecce n t r i c i t y x^{2} + 4 y^{2} = 46