exzentrizität (x^2)/4+(y^2)/3 =1

Lösung

exzentrizität

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1

\frac{1}{2}

Dezimale

0.5

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

\frac{x ^{2}}{4} + \frac{y ^{2}}{3} = 1 :

Ellipse with center

(h, k) = (0, 0), a = 2, b = 3

= \frac{2 ^{2} - ( 3 ) ^{2}}{2}

\frac{2 ^{2} - ( 3 ) ^{2}}{2} = \frac{1}{2}

= \frac{1}{2}

ecce n t r i c i t y \frac{x ^{2}}{169} + \frac{y ^{2}}{25} = 1

ecce n t r i c i t y 16 x^{2} + 9 y^{2} + 160 x - 72 y + 544 = 144

ecce n t r i c i t y \frac{x ^{2}}{25} + \frac{y ^{2}}{64} = 1

ecce n t r i c i t y x^{2} + 9 y^{2} + 16 x + 18 y + 64 = 0

ecce n t r i c i t y x^{2} + 42 y^{2} = 42