exzentrizität 2x^2+3y^2+4x=1

Lösung

exzentrizität

2 x^{2} + 3 y^{2} + 4 x = 1

\frac{1}{3}

Dezimale

0.57735 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

2 x^{2} + 3 y^{2} + 4 x = 1 :

Ellipse with center

(h, k) = (- 1, 0), a = \frac{3}{2}, b = 1

= \frac{( \frac{3}{2} ) ^{2} - 1 ^{2}}{\frac{3}{2}}

\frac{( \frac{3}{2} ) ^{2} - 1 ^{2}}{\frac{3}{2}} = \frac{1}{3}

= \frac{1}{3}

ecce n t r i c i t y 25 x^{2} + 16 y^{2} + 100 x - 96 y - 156 = 0

ecce n t r i c i t y 18 x^{2} + 8 y^{2} + 36 x - 32 y - 22 = 0

ecce n t r i c i t y \frac{x ^{2}}{5} + \frac{y ^{2}}{4.58} = 1

ecce n t r i c i t y 3 x^{2} + 2 y^{2} - 12 x + 8 y + 19 = 0

ecce n t r i c i t y \frac{x ^{2}}{196} + \frac{y ^{2}}{121} = 1