exzentrizität 3x^2+7y^2=63

Lösung

exzentrizität

3 x^{2} + 7 y^{2} = 63

\frac{2}{7}

Dezimale

0.75592 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

3 x^{2} + 7 y^{2} = 63 :

Ellipse with center

(h, k) = (0, 0), a = 21, b = 3

= \frac{( 21 ) ^{2} - 3 ^{2}}{21}

\frac{( 21 ) ^{2} - 3 ^{2}}{21} = \frac{2}{7}

= \frac{2}{7}

ecce n t r i c i t y \frac{x ^{2}}{160} + \frac{y ^{2}}{16} = 1

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ecce n t r i c i t y \frac{x ^{2}}{144} + \frac{y ^{2}}{169} = 1

ecce n t r i c i t y \frac{x ^{2}}{4} + \frac{y ^{2}}{1} = 1