exzentrizität x^2+4y^2-16=0

Lösung

exzentrizität

x^{2} + 4 y^{2} - 16 = 0

\frac{3}{2}

Dezimale

0.86602 \dots

Schritte zur Lösung

= \frac{a ^{2} - b ^{2}}{a}

Calculate ellipse properties

x^{2} + 4 y^{2} - 16 = 0 :

Ellipse with center

(h, k) = (0, 0), a = 4, b = 2

= \frac{4 ^{2} - 2 ^{2}}{4}

\frac{4 ^{2} - 2 ^{2}}{4} = \frac{3}{2}

= \frac{3}{2}

ecce n t r i c i t y 36 x^{2} + 9 y^{2} = 324

ecce n t r i c i t y \frac{x ^{2}}{3} + \frac{y ^{2}}{5} = 1

ecce n t r i c i t y \frac{x ^{2}}{16} + \frac{y ^{2}}{9} = 1

ecce n t r i c i t y 14 x^{2} + 9 y^{2} = 126

ecce n t r i c i t y \frac{y ^{2}}{64} + \frac{x ^{2}}{36} = 1