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Beliebt Geometry >

center 12x^2+20y^2-12x+40y-37=0

Lösung

center

12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

Lösung

(\frac{1}{2}, - 1)

Schritte zur Lösung

12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

Rewrite

12 x^{2} + 20 y^{2} - 12 x + 40 y - 37 = 0

in the form of the standard ellipse equation

\frac{( x - \frac{1}{2} ) ^{2}}{( 5 ) ^{2}} + \frac{( y - ( - 1 ) ) ^{2}}{( 3 ) ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (\frac{1}{2}, - 1), a = 5, b = 3

a > b

therefore

a

is semi-major axis and

b

is semi-minor axis

Ellipse with center (h, k) = (\frac{1}{2}, - 1), a = 5, b = 3

And the center is:

(\frac{1}{2}, - 1)

Graph

Beliebte Beispiele

center 2x^2+y^2+12x-6y+26=0

ce n t er 2 x^{2} + y^{2} + 12 x - 6 y + 26 = 0

center 25x^2+144y^2=900

ce n t er 25 x^{2} + 144 y^{2} = 900

center 2x^2+y^2=50

ce n t er 2 x^{2} + y^{2} = 50

center ((x-h)^2)/(a^2)+((y-k)^2)/(b^2)=1

ce n t er \frac{( x - h ) ^{2}}{a ^{2}} + \frac{( y - k ) ^{2}}{b ^{2}} = 1

center 13x^2+49y^2=637

ce n t er 13 x^{2} + 49 y^{2} = 637