foki ((x+1)^2)/(25)+(y^2)/(16)=1

Lösung

foki

\frac{( x + 1 ) ^{2}}{25} + \frac{y ^{2}}{16} = 1

(2, 0), (- 4, 0)

Schritte zur Lösung

(h + c, k), (h - c, k)

Calculate ellipse properties

\frac{( x + 1 ) ^{2}}{25} + \frac{y ^{2}}{16} = 1 :

Ellipse with center

(h, k) = (- 1, 0), a = 5, b = 4

(- 1 + c, 0), (- 1 - c, 0)

Compute

c :

c = 5^{2} - 4^{2} : 3

(- 1 + 3, 0), (- 1 - 3, 0)

Fasse zusammen

(2, 0), (- 4, 0)

f oc i 9 x^{2} + 4 y^{2} + 54 x - 8 y + 49 = 0

f oc i \frac{( x - 11 ) ^{2}}{63} + \frac{( y - 13 ) ^{2}}{81} = 1

f oc i \frac{( x - 7 ) ^{2}}{144} + \frac{( y - 4 ) ^{2}}{128} = 1

f oc i \frac{( x + 20 ) ^{2}}{105} + \frac{y ^{2}}{16} = 1

f oc i 16 x^{2} + 36 y^{2} = 576