((x-1)^2)/9+((y+2)^2)/(16)=1

Lösung

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{16} = 1

(h, k) = (1, - 2), a = 3, b = 4

Schritte zur Lösung

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{16} = 1

Rewrite

\frac{( x - 1 ) ^{2}}{9} + \frac{( y + 2 ) ^{2}}{16} = 1

in the form of the standard ellipse equation

\frac{( x - 1 ) ^{2}}{3 ^{2}} + \frac{( y - ( - 2 ) ) ^{2}}{4 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (1, - 2), a = 3, b = 4

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (1, - 2), b = 4, a = 3

144 x^{2} + 169 y^{2} - 288 x + 676 y - 33516 = 0

25 x^{2} + 50 x + 4 y^{2} - 16 y = 59

3 x^{2} + 8 y^{2} + 12 x + 48 y + 60 = 1

\frac{( x - 1 ) ^{2}}{4} + \frac{y ^{2}}{9} = 1

25 x^{(2)} + 16 y^{(2)} = 400