((X-2)/2)^2+((Y+3)/4)^2=1

解

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

(h, k) = (2, - 3), a = 2, b = 4

解答ステップ

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

(\frac{X - 2}{2})^{2} + (\frac{Y + 3}{4})^{2} = 1

を標準的な楕円のequationの形式で書き換える

\frac{( X - 2 ) ^{2}}{2 ^{2}} + \frac{( Y - ( - 3 ) ) ^{2}}{4 ^{2}} = 1

ゆえに楕円の特性は:

(h, k) = (2, - 3), a = 2, b = 4

b > a

ゆえに

b

は半長径,

a

は半短径である

中心が (h, k) = (2, - 3), b = 4, a = 2 の楕円