((x^2))/(16)+((y^2))/(25)=1

Lösung

\frac{( x ^{2} )}{16} + \frac{( y ^{2} )}{25} = 1

(h, k) = (0, 0), a = 4, b = 5

Schritte zur Lösung

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

Rewrite

\frac{x ^{2}}{16} + \frac{y ^{2}}{25} = 1

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( y - 0 ) ^{2}}{5 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 5

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 5, a = 4

(\frac{x ^{2}}{9}) + (\frac{y ^{2}}{16}) = 1

16 x^{2} + 25 y^{2} + 160 x + 200 y + 400 = 0

36 x^{2} + 5 y^{2} + 216 x - 60 y + 324 = 0

x^{2} + 4 y^{2} + 8 x + 9 y - 9 = 0

17 x^{2} + 1 0^{2} x + 10 y^{2} + 80 y + 143 = 0