x=-y^2+2y

Lösung

x = - y^{2} + 2 y

(h, k) = (1, 1), p = - \frac{1}{4}

Schritte zur Lösung

x = - y^{2} + 2 y

Rewrite

x = - y^{2} + 2 y

in the standard form

4 (- \frac{1}{4}) (x - 1) = (y - 1)^{2}

Therefore parabola properties are:

(h, k) = (1, 1), p = - \frac{1}{4}

2 x^{2} - x + y = 1

x = \frac{y ^{2}}{2}

y^{2} - 6 y - 2 x + 7 = 0

(x - 2)^{2} = 12 (y - 1)

y^{2} - 4 y - 8 x - 28 = 0