((x+3)^2)/(64)+((y-6)^2)/(100)=1

Lösung

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

(h, k) = (- 3, 6), a = 8, b = 10

Schritte zur Lösung

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

Rewrite

\frac{( x + 3 ) ^{2}}{64} + \frac{( y - 6 ) ^{2}}{100} = 1

in the form of the standard ellipse equation

\frac{( x - ( - 3 ) ) ^{2}}{8 ^{2}} + \frac{( y - 6 ) ^{2}}{1 0 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (- 3, 6), a = 8, b = 10

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (- 3, 6), b = 10, a = 8

16 - x^{2} - 9 y^{2} = 0

256 x^{2} - 800 x + 625 = 400 x^{2} - 800 x + 400 y^{2} + 400

- 2 = \frac{2 x}{x ^{2} + y ^{2}}

16 - x^{2} - 9 y^{2} > 0

8 x^{2} - 96 x + 18 y^{2} + 144 y + 288 = 0