(x^2)/4+(z^2)/(16)=4

Lösung

\frac{x ^{2}}{4} + \frac{z ^{2}}{16} = 4

(h, k) = (0, 0), a = 4, b = 8

Schritte zur Lösung

\frac{x ^{2}}{4} + \frac{z ^{2}}{16} = 4

Rewrite

\frac{x ^{2}}{4} + \frac{z ^{2}}{16} = 4

in the form of the standard ellipse equation

\frac{( x - 0 ) ^{2}}{4 ^{2}} + \frac{( z - 0 ) ^{2}}{8 ^{2}} = 1

Therefore ellipse properties are:

(h, k) = (0, 0), a = 4, b = 8

b > a

therefore

b

is semi-major axis and

a

is semi-minor axis

Ellipse with center (h, k) = (0, 0), b = 8, a = 4

\frac{( x - 2 ) ^{2}}{100} + \frac{y ^{2}}{36} = 1

\frac{( x + 2 ) ^{2}}{16} + \frac{( y - 3 ) ^{2}}{49} = 1

\frac{( x - 1 ) ^{2}}{36} + \frac{( y + 2 ) ^{2}}{16} = 1

\frac{( x - 1 ) ^{2}}{16} + \frac{( y + 2 ) ^{2}}{25} = 1

3 X^{2} + 2 Y^{2} = 8